Session 17 Notes, Section 8-4
Hypothesis Testing: t Tests (Student t Test) for Means - Small
Samples
In the previous sessions, we learned the classical and P-value methods for
test for a mean in the case of "large" samples. In this session we will
explore the testing of the mean when we have "small samples". We will use
both the classical and P-value methods.
At the end of this session you will be able to:
If you have learned all of these objectives, then close this window to
return to where you were.
This test goes by two different names: t Test or Student t Test.
-
The t test is a statistical test of the
mean of a population and is used when
the population is normally or
approximately normally distributed,
σ is
unknown, and the sample size
≤ 30.
- The formula for the t test is:
- The degrees of freedom are d.f. =
n–1.\
In the Classical or Traditional Method of solving problems with the t test is done using the same method as with the
z text EXCEPT that t values are found on the T table (Table F of your
textbook) instead of using Z values
found on the Z table (Table E of your textbook).
P-values for the t test can only be found for intervals using Table F in your
book. You use the value that is lower than and above the actual value you
are looking up to be the interval in which the p-value would lie.
Return to objectives
- Find the critical value for α= 0.05
with d.f. = 12 for a right-tailed t test.
- Go to table F page 731
- Find the 0.05 column in the top row and 12 in the left-hand column.
- Where the row and column meet, the appropriate critical value is
found: it is +1.782
- Find the critical values for α= 0.50
with d.f. = 18 for a two-tailed t test.
- Go to table F page 731
- Find the 0.50 column in the row labeled "Two tails", and find 18 in
the column labeled "d.f.".
- The critical values are: +0.688 and -0.688.
Return to objectives
A job placement director claims that the average starting salary for nurses
is $26000. A sample of 14 nurses has a mean of $25560 and a standard deviation
of $500. Is there enough evidence to reject the director's claim at
α= 0.05?
- Review the steps for hypotheses testing.
Follow them step by step.
- Step 1: State the hypotheses and identify the claim.
- H0: µ = 26000 (claim) and H1: µ
not = 26000
- Step 2: Find the critical value.
- The critical values are +2.16 and -2.16 for = 0.05 and d.f. = 13
- Step 3: Compute the test value.
-
or
= -3.29
- Step 4: Make the decision.
- Reject the null hypothesis, since -3.29 < -2.16.
- Step 5: Summarize the results.
- There is enough evidence to reject the claim that the starting salary of
nurses is $26000.
Return to objectives
- Step 1 State the hypothesis, and identify the claim.
- Step 2 Find the critical value from the appropriate table.
- Step 3 Compute the test value using
t = (X -
μ) /(
s/√n).
- Step 4 Make the decision to reject or not reject the null hypothesis.
- Step 5 Summarize the results.
Return to objectives
When you finish these notes, then close this window to return to where
you were.